(x^(2/3)y^(5/6))/(x^(-1/3)y^(1/2))

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Solution for (x^(2/3)y^(5/6))/(x^(-1/3)y^(1/2)) equation: 


D( x )

x = 0

x^(-1/3)*y^(1/2) = 0

x = 0

x = 0

x^(-1/3)*y^(1/2) = 0

x^(-1/3)*y^(1/2) = 0

x^(-1/3)*y^(1/2) = 0 // : y^(1/2)

x^(-1/3) = 0

x należy do O

x in (-oo:0) U (0:+oo)

(x^(2/3)*y^(5/6))/(x^(-1/3)*y^(1/2)) = 0

x*y^(1/3) = 0 // : y^(1/3)

x = 0

x in { 0} 

x belongs to the empty set

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